Total number of seven digits ,, sum of whose digits is even .. (repitition is allowed)
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total number of 7 digits numbers is (9999999-1000000+1).out of 9000000numbers 4500000 are having the sum of digits as even and the remaining 4500000 are having the sum of digits as odd. since every alternate number has its sum of digits even and odd so the required number is 4500000
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