Question

Total number of sugar molecules present in 100ml of 0.1M sugar C12H22O11 solution is
a.6.02 x 10²¹
b.6.02 x 10²³
c.6.02 x 10^20
d. 6.02 x 10²²​

Answer 1

ANSWER IS A

$100 ml$ of $0.1M$ sugar

then 1 mole = 6.022 × 10²³ of substance then the $0.1 *6.022*10^23 = 6.02*10^21$

Answer 2

Correct answer is Option (a) 6.023 ×10²¹

Explanation:

Molar mass of Sugar (C₁₂H₂₂O₁₁) is 342 gm

volume of solution =100ml (0.1L)

Molarity = 0.1M

Mole =Volume of solution in litre × concentration

= 0.1 ×0.1

=0.01 mole

Total number of sugar molecules = moles of sugar × 6.023 ×10²³

=0.01 × 6.023 ×10²³

=6.023 ×10²¹

The Answer is Option (a) Total number of sugar molecules is calculated as 6.023 ×10²¹