Total number of valence electrons in 4.2 g of azide ion
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4.2 g X (1 mol/14 g) = 0.3 mol N3-
Number of N3- ions = 0.3 mol X 6.02 X10^23 ions/mol = 1.8 X 10^23 ions.
Each N3- ion has 8 valence electrons, so total number of valence electrons =1.8 X 10^23 X 8 = 1.4 X 10^24 valence electrons.
Number of N3- ions = 0.3 mol X 6.02 X10^23 ions/mol = 1.8 X 10^23 ions.
Each N3- ion has 8 valence electrons, so total number of valence electrons =1.8 X 10^23 X 8 = 1.4 X 10^24 valence electrons.
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