Total pressure exerted by mixture of two gases A and B is 600 mm of Hg. If partial pressure of gas A and B is 240 mm of Hg. Calculate Partial pressure of gas B and mole fraction of A and B.
Answers
Answered by
2
Answer:
Partial pressure of gas = Mole fraction of gas×P
Total
=.35×24=8.4 atm
As the mole fraction of B,C gas are same.
Answered by
0
Answer:
Correct option is
A
8.4
Partial pressure of gas = Mole fraction of gas×P
Total
=.35×24=8.4 atm
As the mole fraction of B,C gas are same.
Similar questions