Question

Total pressure exerted by mixture of two gases A and B is 600 mm of Hg. If partial pressure of gas A and B is 240 mm of Hg. Calculate Partial pressure of gas B and mole fraction of A and B.

Answer 1

Answer:

Partial pressure of gas = Mole fraction of gas×P

Total

=.35×24=8.4 atm

As the mole fraction of B,C gas are same.

Answer 2

Answer:

Correct option is

A

8.4

Partial pressure of gas = Mole fraction of gas×P

Total

=.35×24=8.4 atm

As the mole fraction of B,C gas are same.