Question

Total pressure on 1 m x 1 m gate immersed vertically at a depth of 2 m below the free water surface will be

Answer 1

please mark it as brainliest answer please

answer should be 2500 kg.

since 2m vertically downward from free surface.

therefore COG from free surface equal to (2+1/2)=2.5m

using formula for

pressure = W*A*X

= (9.81*1000) * (1*1)*2.5 N

= 2500 kg (answer)

(1Kgf=9.81N)

Answer 2

Total pressure on vertical plate = 2500 kg

Given:

Cross section area of plate =  1 m x 1 m

Immersed vertically at a depth of 2 m below the free water surface.

To find:

Total pressure on plate.

Formula used:

Total pressure on vertical plate = $\rho g A \bar{X}$

Where $\bar{X}$ = Distance of center of gravity of plate from free surface of water.

            A = Cross section area of plate

            $\rho$ = Density of water = $10^3$

Explanation:

Center of gravity of plate = $\frac{1}{2}$ = 0.5m

And this plate is 2m below the surface of the water

So that,

Distance of center of gravity of plate from free surface = 2+0.5 = 2.5 m

Total pressure on vertical plate = $\rho g A \bar{X}$

Total pressure on vertical plate = $10^3$ × 10 ×1×1 × 2.5

                                                     = 25000 N ≅ 2500 kg

Total pressure on vertical plate = 2500 kg

To learn more...

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(A) 0.02 bar

(B) 0.04 bar

(C) 0.016 bar

(D) 0.2 bar

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