Question

total spin and magnetic moment for oxygen atom are A)+-1,root 8BM B)+-2,6.93BM C)+-1,root 15BM D)+-2,root 48BM

Answer 1

Concept: The square root of S(S + 1), where S is either an integer or half an odd integer depending on whether there are more even or more odd numbers of electrons, is the magnitude of the total spin momentum. All conceivable electron orientations within the atom can be used to determine the potential value of the total spin angular momentum.

The measurement of an object's propensity to line up with a magnetic field is known as a magnetic moment, sometimes known as a magnetic dipole moment. The magnetic pull and direction of a magnet or other item that generates a magnetic field are known as the "Magnetic Moment" A vector quantity is the magnetic moment.

Given: question regarding total spin and magnetic moment for oxygen atom

To find: total spin and magnetic moment for oxygen atom

Solution: Refer the figure for configuration filling

for oxygen atom (O), the configuration is  $1s^2 2s^2 2p^4$

thus,

$S = 2 * \frac{1}{2}$    or   $2 * \frac{-1}{2}$

  =  +1 or -1

Magnetic moment =

$\sqrt{n(n+2)} \\\\\sqrt{2(2+2)}\\ \\\sqrt{2 * 4} = \sqrt{8}$

Hence, total spin for oxygen atom is ±1

and magnetic moment for oxygen atom is $\sqrt{8}$ BM.

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