Question

Total spin resulting from a d^5 configuration is? (Class 11 chemistry)

Answer 1

Explanation:

Total spin S = ( 1/2+1/2+1/2+1/2+1/2) = 5/2

electron is represented by either +1/2(for clockwise rotation direction) or -1/2 (Anticlockwise rotation direction).

in d5, there are total 5 unpaired electron and each electron in each orbital will be either +1/2 or -1/2.

so total spin multiplicity = 2*S +1 = 2* 5/2 +1 = 6

here's the answer key and hope this helps you.