Question

total surface area of a cylinder is 4224cm^2 it is a cut it height and from the rectangular sheet of acquired 33 cm find the perimeter of a rectangular sheet​

Answer 1

Answer:

Explanation:

Lateral surface area =2\pi rh=4224\ cm^22πrh=4224 cm  

2

 

2\times\frac{22}{7}\times r\times h=4224\ cm^22×  

7

22

​  

×r×h=4224 cm  

2

 

rh=\frac{4224\times7}{22\times2}  

22×2

4224×7

​  

 

rh=672 -1

Width of rectangle=circumference of cylinder

33=2\pi r33=2πr

33=2\times\frac{22}{7}\times r33=2×  

7

22

​  

×r

\frac{33\times7}{2\times22}=r  

2×22

33×7

​  

=r

r=5.25 cm

substituting r=5.25 cm - 1

5.25 h=672

h=128 cm

Now,for rectangular sheet,

l=128 cm b=33 cm

perimeter=2\left(l+b\right)2(l+b)

=2\left(128+33\right)2(128+33)

=2(161)

=322 cm

Answer 2

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