total surface area of a cylinder is 4224cm^2 it is a cut it height and from the rectangular sheet of acquired 33 cm find the perimeter of a rectangular sheet
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Answer:
Explanation:
Lateral surface area =2\pi rh=4224\ cm^22πrh=4224 cm
2
2\times\frac{22}{7}\times r\times h=4224\ cm^22×
7
22
×r×h=4224 cm
2
rh=\frac{4224\times7}{22\times2}
22×2
4224×7
rh=672 -1
Width of rectangle=circumference of cylinder
33=2\pi r33=2πr
33=2\times\frac{22}{7}\times r33=2×
7
22
×r
\frac{33\times7}{2\times22}=r
2×22
33×7
=r
r=5.25 cm
substituting r=5.25 cm - 1
5.25 h=672
h=128 cm
Now,for rectangular sheet,
l=128 cm b=33 cm
perimeter=2\left(l+b\right)2(l+b)
=2\left(128+33\right)2(128+33)
=2(161)
=322 cm
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