Question

Total surface area of cuboid of dimension of a,2a,3a is

Answer 1

TSA=2(lb+bh+hl)
TSA= 2(a×2a+2a×2a+3a×a)= 18a^2

Answer 2

Total surface area of cubiod = 2( l b + b h +hl) where l, b, h are length, breadth, height respectively.

So Now Total surface area =2(a*2a+2a*3a+a*3a)

=2(2a²+6a²+3a²)

=2(11a²)

=22a²

therefore,the total surface area of cuboid of dimensions a*2a*3a=22a²