total valence eletron present in XeF4 is a)12 b)18 c)24 d) 36
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Answer:
correct answer is 36
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0
Answer:
36
Explanation:
The valence electron in Xenon tetrafluoride is 36.because Xe has total 8 no. of valence electron and one no. of fluorine has 7 no. of valence electron.Here 4 no. of fluorine is present.So 4 fluorine has 7×4=28 valence electron.The total no. of valence electron is 8+28=36.
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