Question

Total volume of gaseous mixture occupied by using 32g of O2 and 3g of H2 at STP
condition is
1) 22.4 lit
4) 44.8 lit
2) 33.6 lit
3) 56 lit​

Answer 1

no. of moles, n = W / MM = V/22.4

nO2 = 32/32 = VO2/22.4

VO2 = 22.4

nH2 = 3/2 =VH2/22.4

VH2 = 1.5×22.4 = 33.6

Total volume occupied = 22.4 + 33.6

= 56 lit.

Option 3 is correct.

Hope it helps..

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