Total volume of gaseous mixture occupied by using 32g of O2 and 3g of H2 at STP condition is
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Explanation:
No. of moles for O2 = 32/32 = 1 mole
No. of moles for H2 = 3/2 = 1.5 mole
Since from other formula at STP :
No of moles = V / 22.4
V1 = 1* 22.4 = 22.4
V2 = 1.5*22.4 =33.6
Total volume = V1 + V2 = 56 ltr
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