Math, asked by anshu20199253, 11 months ago

total weight of 3 boxes is 60.5 kg. 2nd box weight 3.5 kg more than 1st box. the 3rd box weighs 2.5 kg more than 2nd box. the weight of 1st box is​

Answers

Answered by labdas742132
1

Step-by-step explanation:

let wet of 1st box is=x

wet of 2nd box =(X+3.5)

wet of 3rd box={wet of 2nd box+2.5}

={(X+3.5)+2.5}

= {x+6}kg

since

the total wet of 3 box=60.5kg

thus,[wet of 1st+wetof 2nd+wet of 3rd]=60.5

[X+X+3.5+X+6]=60.5

3x+9.5=60.5

3x=60.5_9.5

3x=51

X=17

Answered by bednarayanrai
0

Answer:

let 1st 2nd 3rd boxes be x kg,y kg and z kg respectively .

Step-by-step explanation:

I. x + y+ z = 60.5 kg

II. y = x + 3.5

III. z = y + 2.5

I. x + y + z = 60.5

x = 60.5 - y - z

x = 60.5 -(x+3.5) - z

x = 60.5 -x - 3.5 - z

x = 60.5 - x - 3.5 - (y + 2.5)

x = 60.5 -x - 3.5 - ( x + 3.5 + 2.5)

x = 60.5 -x - 3.5 - (x + 6)

x = 60.5 -x - 3.5 -x -6

x = 60.5 -x -x -3.5 -6

x = 60.5 -2x -9.5

x+ 2x = 60.5 - 9.5

3x = 51

x = 51/3 = 17.

II. y = x + 3.5

y= 17 + 3.5

y = 20.5

III. z = y + 2.5

z = 20.5 + 2.5

z = 23

x + y + z = 17 + 20.5 + 23

= 60.5

Therefore weight of the first box is 17kg.

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