Question

Totally 3 beakers A,B,C are present. A of capacity X lit, B of capacity 2X lit, C of capacity 3X lit. if A contain 2/3 of wine and rest with water. B contains 1/4 of wine and rest with water. if these two liquids are poured in to the 3rd beaker what is the proportion of wine in the 3rd beaker.​

Answer 1

Answer:

                      Wine                        Water               Total

Beaker A         2 X / 3                      X / 3                   X

Beaker B         2 X / 4                    3/4 * 2 X           2 X

Total             (2 /3   + 1/2 ) X          (1/3 + 3/2) X

                         7 X / 6                    11 X / 6              3 X

Beaker C         (7 X / 6)  / 3 X      = 7 / 18      wine

                        (11 X / 6) / 3 X        = 11 / 18     water

Answer 2

Answer:

The proportion of wine in the 3rd beaker is $\frac{7}{18}$

Step-by-step explanation:

Given,

Capacity of A = X lit,

Capacity of B = 2X lit,

Also, A contains $\frac{2}{3}$ of wine and B contains $\frac{1}{4}$ of wine,

If these two liquids are poured in to the 3rd beaker C,

Then, the quantity of wine in C = $\frac{2}{3}\times X+\frac{1}{4}\times 2X$

$=\frac{2X}{3}+\frac{2X}{4}$

$=\frac{8X+6X}{12}$

$=\frac{14X}{12}$

$=\frac{7X}{6}\text{ lit}$

Now, capacity of C = 3X lit,

Hence, the proportion of wine in C = $\frac{7X/6}{3X}$

$=\frac{7}{18}$