Question

TOU
udl
An I section girder 12 cm deep has the following cross-
sectional dimensions: Top flange 6 cm wide by 1 cm thick,
bottom flange 12 cm wide by 1 cm thick, web 1 cm thick.
The girder is 5 m long simply supported over a span
of 3 m,
overhanging both supports by the same amount and it carries
a concentrated load of 2 kN each end. Find the maximum
stress in the material due to bending.
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Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

UDL: Universal design learning

An I-section girder 12 cm deep has the following cross-sectional dimensions: Top flange 6 cm wide by 1 cm thick, bottom flange 12 cm wide by 1 cm thick, web 1 cm thick, web 1 cm thick. The girder is 5 m long simply supported over a span of 3 m, overhanging both supports by the same amount and it carries a concentrated load of 2 kN each end. Find the maximum stress in the material due to bending

For a rectangular solid object, I = (b*h^3)/12, where "b" is the width of the cross-section, and "h" is the measure of the cross-section in the direction force is being applied. For a round solid object, I = (pi*r^4)/4, where "r" is the radius of the cross-section.