Question

tough challenge for u all

Answer 1

no of moles of H2 = 10/2 = 5
no of moles of oxygen = 64/32 = 2

Total no of moles = 7

PV =nRT

Substituting the given values

P = 2752700 N/m2

On ignition

2H2+O2--> 2H20

We have 5 moles of H2 and 2 moles of O2

Based on stichiometry 2 moles of O2 will combine with 4 moles of H2 to form 4 moles of H20

Thus 1 mole of hydrogen will be left

Thus no of moles in the vessel = 1(H2)+4(H2O)

PV = nRT

Substituting the values and n= 5 we get

P = 1966261 atm