Question

Tow bodies of different masses m1andm2 dropped from two different height a and b what is the ratio os time taken by the two to drop these distance

Answer 1

t₁/t₂ = $\sqrt{} \frac{a}{b}$

Explanation:

the bodies are under free fall (neglecting air resistance)

acceleration due to gravity g is acting on both of them .

using the equation of motion :

h= ut + 0.5 gt²

as u is 0 for both cases .

h = 0.5 at²

t = $\sqrt{2 h/g}$

t₁/t₂ = $\sqrt{} \frac{a}{b}$