Question

Tow cross roads each of width 10m cut at right angles through the centre of a rectangular park of length 700m and breath 300m and parallel to its sides. Find the area of the roads. Also find the area of the park excluding cross roads. Give the answer in hectares

Answer 1

Answer:

area of roads -- 9900 sq.metres ==0.99 hectares

area of park excluding roads -- 200100 sq.metres == 20.01 hectares

Step-by-step explanation:

area of longer road = 700{length}×10{width of road} = 7000 sq.m

area of shorter road = 300{length}×10{width of road} = 3000 sq.m

common area of roads = 10*10 = 100 sq.m

therefore, area of roads = 7000+3000-100{As we have counted this are       twice for two roads}        =10000-100=9900 sq.m

for the area other than roads, area = 700×300{length×breadth of park}

- 9900{area of roads}

=200100 sq.m

Now, 10000 sq.m=1 hectare ⇒9900 sq.m=9900÷10000=0.99 hectares

similarly area of park = 20.01 hectares..............

Answer 2

Answer:

Step-by-step explanation:area of roads -- 9900 sq.metres ==0.99 hectares

area of park excluding roads -- 200100 sq.metres == 20.01 hectares

Step-by-step explanation:

area of longer road = 700{length}×10{width of road} = 7000 sq.m

area of shorter road = 300{length}×10{width of road} = 3000 sq.m

common area of roads = 10*10 = 100 sq.m

therefore, area of roads = 7000+3000-100{As we have counted this are       twice for two roads}        =10000-100=9900 sq.m

for the area other than roads, area = 700×300{length×breadth of park}

- 9900{area of roads}

=200100 sq.m

Now, 10000 sq.m=1 hectare ⇒9900 sq.m=9900÷10000=0.99 hectares

So, area of park = 20.01 hectares.