tow equal sides of a triangle are each 5 meters less than twice the third side if the perimater of the triangle is 55 meters find the length of its sides
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Given ,
- Two sides of a triangle are equal and are 5 less than twice the third side.
- Perimeter of the triangle is 55 metres
To Find :-
Length of its sides.
Solution :-
Let the third side be x
Twice of x = 2x
Length of two equal sides = (2x - 5)m
Now,
Perimeter = Sum of all three sides.
= (2x - 5) + (2x - 5) + x
According to question ,
(2x - 5) + (2x - 5) + x = 55
=> 5x - 10 = 55
=> 5x = 55 + 10 = 65
=>x = 65/5
= 13
Therefore, x = 13 m
Ist side = (2x - 5)
= 2×13 - 5
= 26 - 5
= 21 m
2nd side = Ist side = 21 m
3rd side = x = 13 m.
Therefore the sides of the triangle are 21m, 21m and 13m respectively.
Verification :-
Perimeter = sum of all sides
=> 55 m = 21m + 21m + 13m
=> 55 m = 42m + 13m
=> 55m = 55m
Since LHS = RHS, Hence Verified.
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