TOW FORCES ,ONE OF 12N ANOTHER OF 24N .ACT ON ABODY IN SUCH AWAY THAT THEY MAKE AN ANGEL OF 90DEGRE WITH EACH OTHER .FIND RESULTANT OF TOW FORCE
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F1 = 12 N
F2 = 24 N
angle between both = 90°
resultant force =√ [(F1)^2 + (F2)^2 + 2 x F1 x F2 x Cosθ ]
F(net) = √ [(12)^2 + (24)^2 + 2 x 12 x 24 x Cos 90 ]
F(net) = √[144 + 576 + 0 ] ,because Cos 90 = 0
F(net) = √720 = 26.83 N
i hope it will help you
regards
F2 = 24 N
angle between both = 90°
resultant force =√ [(F1)^2 + (F2)^2 + 2 x F1 x F2 x Cosθ ]
F(net) = √ [(12)^2 + (24)^2 + 2 x 12 x 24 x Cos 90 ]
F(net) = √[144 + 576 + 0 ] ,because Cos 90 = 0
F(net) = √720 = 26.83 N
i hope it will help you
regards
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