Question

tow numbers are in ratio 5:7.Their difference is 10,find the number.​

Answer 1

Answer:

let two numbers be x and y,

given,

x:y = 5:7 = 5t,7t (where t € N)

and y-x = 10,

=> 7t-5t =10,

=> 2t =10,

=> t = 5.

therefore,the no's will be 5*5,7*5,

= 25,35 are required numbers.

Answer 2

Correct Question :-

• Two numbers are in the ratio 5 : 7$.$
• Their difference is 10. Find the numbers.

Given :-

• Ratio of numbers = 5:7
• Their difference = 10

Have to Find :-

• The numbers = ?

Solution :-

Let's consider the numbers be " 5x " and " 7x " respectively.

So,

According to the Question

↬ 5x - 7x = 10

↬ (- 2x ) = 10

↬ x = 10/-2

↬ x = ( -5)

Now,

• First number = 5x

⇒ 5 × (-5) = - 25

• Second Number = 7x

⇒ 7 × (-5) = - 35

Therefore, the numbers are (-25) and (-35) respectively.

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