Question

tow objects A and B dropped from a height the object B being dropped . S after A was dropped . how long after A was dropped will A and B be 10 m apart​

Answer 1

Answer:

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Answer 2

Answer:

Two objects A and B dropped from a height the object B being dropped . S after A was dropped . how long after A was dropped will A and B be 10 m apart​.

Explanation:

In the above question there are two objects. Objects A and B. which are dropped from the height. After object A was dropped B was also dropped.

So from given information we come to know- Acceleration due to gravity is 10, and final distance minus initial distance is 10m.

So we have to find the total time after how long A will dropped.

For solving this we will use the formula of- S= 1/2 att.

Therefore-

$S= \frac{1}{2}\times a\times t^{2} \\S1= \frac{1}{2} \times 10\times t^{2} \\S2= \frac{1}{2}\times 10 \times -1^{2}$

there fore, S1- S2= 10m

$St^{2} -5 ((t-1)^{2} )=0\\5t^{2}-5(t^{2} +1-2t)=0\\10t-5=10\\10t=15\\t= 1.5sec$

Hence From solving above question we come to know the value of times is 1.5 sec.

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