Question

tow pipes togther can fill a water tank in 6 min if one of the pipe takes 5min more than that of other to fill the tank find the time taken by each pipe to fill the tank​

Answer 1

SORRY YAR I DON'T KNOW THE ANSWER

Answer 2

Answer:

Let the time taken by the two pipes to fill the cistern be x and x + 5 min. respectively.

In 1 min., the first pipe can fill 1/x of the cistern. In 1 min., the second pipe can fill 1/x + 5 of the cistern then

1/x + 1/x + 5 = 1/6

⇒  x + 5 + x/x(x + 5) = 1/6

⇒ 2x + 5/x2 + 5x = 1/6

⇒  x2 + 5x  = 12x + 30

⇒ x2 – 7x – 30 = 0

⇒ x2 – 10x + 3x – 30 = 0

⇒ x(x – 10) + 3(x – 10) = 0

⇒ (x – 10)(x + 3) = 0

⇒ x – 10 = 0  or  x = - 3

⇒ x = 10  or  x =  - 3

Since,  time can not be negative.

So, x = 10 and  x + 5 = 10 + 5 = 15