Question

Tow point charges of +5 C are so
placed that they experience a force of
8.010-3N. They are then moved apart,
so that the force is now 2.010-3N. The
distance between them is now
(A) 1/4 the previous distance
(B) double the previous distance
(C) four times the previous distance
(D) half the previous distance
​

Answer 1

Answer:

c four times the previous danstace