Question

Tower stands on the centre of the circular Park .A and B are the two points on the circumference of the park and diameter about substance and angle of 60 degree with the foot of the tower and angle of elevation of the top of the tower from the point B is 30 degree find the height of the tower​

Answer 1

Answer:

let foot of the tower be at point 'C'

and height be "h" ,since tower stands at the centre of circular park so therefore distance from the foot of the tower will be equal to both points A&B(AC& BC r radii of circular park).

let AC = a

so AC = BC = a

angle of elevation = 30°

Tan30° = h/a

1/√3 = h/a => h = a/√3 Answer