Town X is 6km away and on a bearing of 030° from Y. Town Z is 8km from Town X and on a bearing of 120° . Calculate, correct to nearest whole number, the bearing of Z from Y.
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Step-by-step explanation:
A, B and C are three ships. The bearing of A from B is 045º. The bearing of C from A is 135º. If AB= 8km and AC= 6km, what is the bearing of B from C?
bearings
tanC = 8/6, so C = 53.13º
y = 180º - 135º = 45º (interior angles)
x = 360º - 53.13º - 45º (angles round a point)
= 262º (to the nearest whole number)
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