Math, asked by robinhooda1, 10 months ago

towns A and B are 400 km apart Rohan started his car from a m o b and at the same time Rahul started his car from B and route towards a after 3 hours there were 10 kilometre apart if Rohan speed exceeds Rahul speed by 10 kilometres per hour find their respective speed​

Answers

Answered by rudraaggarwal239982
24

Answer:

here is yoru answer mate...

Step-by-step explanation:

Let the speed of Jagdish car be x km/hour.

∴ Speed of Prakash car be (x + 10) km/hour.

In 5 hours Jagdish and Prakash traveled 5x km and 5(x + 10) km respectively. Total distance travelled by them = (400 - 10) km =390 km.

∴ 5x + 5(x + 10) = 390

⇒ 10x + 50 = 390

⇒ 10x = 340

⇒ x = 34

Speed of Jagdish car = 34 km/hour.

Speed of Prakash car = (34 + 10) km/hour = 44 km/hour.

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robinhooda1: Bhai who r jagdish and prakash??
robinhooda1: Rohan and rahul
robinhooda1: Rohan and rahul
rudraaggarwal239982: yes
rudraaggarwal239982: went by mistake
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