Math, asked by muruganraji4413, 4 months ago

TP and TQ are the tangents to a circle with Centre O so that <POQ=100°, then <PTQ is

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Answers

Answered by mathdude500

0

Answer:

As OP is perpendicular to TP

So, /_TPO = 90

As OQ is perpendicular to TQ

So, /_TQO = 90

IN QUADRILATERAL OPTQ

/_TPO + /_TQO + /_POQ + /_PTQ = 360

90 + 90 + 100 + /_PTQ = 360

/_PTQ = 360 - 280 = 80

Answered by suman8615

1

Answer:

this is correct......................

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