Question

TP and TQ are two tangents to a circle with centre O so that angle POQ =110 degree then angle PTQ is equal to

60 degree

70 degree

80 degree

90 degree​

Answer 1

Answer:

Angle PTQ is equal to 70 degree.

Answer 2

Step-by-step explanation:

TP and TQ are tangent to a circle with O

Radius drawn from the centre to ponit of contact will be right angle

so OTP+TPQ+POQ+QOT=360

90+90+110+PTQ=360

PTQ=360-290

PTQ=70

Hope you understand

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