Question

√TPQ = 111° and √TRS = 164° find the value of x​

Answer 1

Answer:x =164 -111=53

Step-by-step explanation:

Answer 2

Answer:

Sol: By linear pair property of angle;

TPQ +RPQ =180°

111° + RPQ = 180°

RPQ = 180° - 111°

RPQ = 69°

Again ,By linear pair property of angle ;

PRQ + PRS = 180°

PRQ + 164° =180°

PRQ = 180° - 164°

PRQ = 16°

NOW, In PQR ,By Exterior angle property of triangle ;

Exterior angle = Sum of opposite interior angle

UQS = RPQ + PRQ

X = 69° + 16°

X = 85°