Question

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A car starting from 3m/s acquires avelocity of 7m/s in 2s .Calculate the acceleration.If 7N force acting on the car find mass of car.

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Answer 1

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Step-by-step explanation:

u= 3m/s

v=7m/s

t=2s

a=(v-u)/t

a= (7-3)/2 =2m/s^2

F=7N

F=ma

7=m×2

m = 3.5 kg

Answer 2

Answer:

Here,

Here,initial velocity of car(u)=0ms

Here,initial velocity of car(u)=0ms −1

Here,initial velocity of car(u)=0ms −1

Here,initial velocity of car(u)=0ms −1 final velocity of car (v)=30ms

Here,initial velocity of car(u)=0ms −1 final velocity of car (v)=30ms −1

Here,initial velocity of car(u)=0ms −1 final velocity of car (v)=30ms −1

Here,initial velocity of car(u)=0ms −1 final velocity of car (v)=30ms −1 time(t)=10s

Here,initial velocity of car(u)=0ms −1 final velocity of car (v)=30ms −1 time(t)=10swe know,

Here,initial velocity of car(u)=0ms −1 final velocity of car (v)=30ms −1 time(t)=10swe know,v=u+at

Here,initial velocity of car(u)=0ms −1 final velocity of car (v)=30ms −1 time(t)=10swe know,v=u+at30=0+a(10)

Here,initial velocity of car(u)=0ms −1 final velocity of car (v)=30ms −1 time(t)=10swe know,v=u+at30=0+a(10)a=3ms

Here,initial velocity of car(u)=0ms −1 final velocity of car (v)=30ms −1 time(t)=10swe know,v=u+at30=0+a(10)a=3ms −2

Here,initial velocity of car(u)=0ms −1 final velocity of car (v)=30ms −1 time(t)=10swe know,v=u+at30=0+a(10)a=3ms −2

Here,initial velocity of car(u)=0ms −1 final velocity of car (v)=30ms −1 time(t)=10swe know,v=u+at30=0+a(10)a=3ms −2 we know,

Here,initial velocity of car(u)=0ms −1 final velocity of car (v)=30ms −1 time(t)=10swe know,v=u+at30=0+a(10)a=3ms −2 we know,F=ma

Here,initial velocity of car(u)=0ms −1 final velocity of car (v)=30ms −1 time(t)=10swe know,v=u+at30=0+a(10)a=3ms −2 we know,F=ma=1500×3

Here,initial velocity of car(u)=0ms −1 final velocity of car (v)=30ms −1 time(t)=10swe know,v=u+at30=0+a(10)a=3ms −2 we know,F=ma=1500×3or F=4500N

Step-by-step explanation:

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