Question

) (TR)X [E3JFC-5) = [C-18) XC-31]+[C-18) XC-5)]
U​

Answer 1

Answer:

1=

x

)

−5)

⇒ 9y=x

⇒ E(C,

5

C

)

Area of △OAB=

2

1

×h×AB=

2

1

×1×8=4

⇒ Area of BDE=

2

4

=2

⇒

2

1

∣

∣

∣

∣

∣

∣

∣

∣

∣

C

9

C

1

1

5

C

1

1

1

∣

∣

∣

∣

∣

∣

∣

∣

∣

R

1

→R

1

−R

2

⇒

2

1

∣

∣

∣

∣

∣

∣

∣

∣

∣

C−9

9

C

0

1

5

C

1

1

1

∣

∣

∣

∣

∣

∣

∣

∣

∣

=

∣

∣

∣

∣

∣

∣

2

1

(C−5)(1−

5

C

∣

∣

∣

∣

∣

∣

=2⇒∣(C−9)(5−C)∣=36⇒

∣

∣

∣

∣

−(C−9)

2

∣

∣

∣

∣

=36⇒(C−9)

2

=36⇒C−9=±6⇒C=15or3