Trace curve of r=2+3cos (theta)
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Find the area enclosed by the curve:
r=2+3cosθr=2+3cosθ
Here's my steps:
since when r=0r=0, cosθ=0cosθ=0 or cosθ=arccos(−2/3)cosθ=arccos(−2/3).
so the area of enclosed by the curve is 2*(the area bounded by θ=arccos(−2/3)θ=arccos(−2/3) and θ=0θ=0)
the answer on my book is 55–√+(17/2)∗arccos(−2/3)55+(17/2)∗arccos(−2/3)
I have no idea why there is a 55–√55 since arccos(−2/3)=2.300523984arccos(−2/3)=2.300523984 on my calculator.
r=2+3cosθr=2+3cosθ
Here's my steps:
since when r=0r=0, cosθ=0cosθ=0 or cosθ=arccos(−2/3)cosθ=arccos(−2/3).
so the area of enclosed by the curve is 2*(the area bounded by θ=arccos(−2/3)θ=arccos(−2/3) and θ=0θ=0)
the answer on my book is 55–√+(17/2)∗arccos(−2/3)55+(17/2)∗arccos(−2/3)
I have no idea why there is a 55–√55 since arccos(−2/3)=2.300523984arccos(−2/3)=2.300523984 on my calculator.
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This is ur answers hope it will help u
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