Question

train 200 m long enters at 5 m/s and exits at 3 m/s from a bridge 300 m long. The time taken by it is

Answer 1

Answer:

ok lets see

train length 200m

speed 5ms

speed 2 = 3ms

bridge legth

so answer will bee

Explanation:

Total distance S = 200 + 300 = 500m

Initial velocity u = 3m/s

Final velocity v = 5 m/s

We know,  

v​​​​​² ​​​​​- u​​​² = 2as

=> 25 - 9 = 1000a

=> a = (16/1000)m/s²

Again  

v = u + at

=> 5 = 3 + (16/1000)t

=> t = 2 × (1000/16) = 125 s = 2 minutes 5 second

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