TRAIN 920 M LONG PASSES A PLATFORM 520 M LOn 48 sec. find the speed of the train.
Answers
Answered by
1
Answer:
the train passes (920+520)m in 48 sec
speed if the train =1440/48 m/sec
=30 m/sec
Answered by
0
Answer:
30 m/sec
Step-by-step explanation:
The length of Train = 920m
the length of platform = 520m
The total Distance that to be covered is=920+520
=1440 m
The time taken to cover the distance =48 sec
The speed = Distance covered/ Time taken
=1440/48
30m/sec = 108 Km/hr
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