Question

Train-a crosses a stationary train b in 35 seconds and a pole in 14 seconds with the same speed. The length of the train-a is 280 metres. What is the length of the stationary train-b?

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Non of these

Step-by-step explanation:

Given:

Train A crosses a stationary Train B in 50 sec.

Train A crosses a pole in 20 sec.

Speed is same in both case.

To find:

Lenght of train B

Point To be remembered

1)Crossing a pole means travelling own lenght.

2) \sf Speed(s)= \dfrac{Distance(x)}{Time(t)}Speed(s)=

Time(t)

Distance(x)

How to find:

First we will find the speed of train by using above formula then we will find the required length.

Solution:

t = 20 sec

x = 240 m [from 1]

s = ?

As we know,

\begin{gathered}\sf s= \dfrac{x}{t} \\ \sf \: s = \dfrac{240}{20}\\ \sf s=12\end{gathered}

s=

t

x

s=

20

240

s=12

Now,

s = 12 m/sec

t = 50 sec

x = ?

Again,

\begin{gathered}\sf \: x \:= s \times t \\ \sf = 12 \times 50 \\ = 600 \: m\end{gathered}

x=s×t

=12×50

=600m

The required length of Train B is 600 m and our final answer is non of these.