Train A, traveling 70 mph, leaves Westford heading toward Eastford, 260 miles away. One hour after Train A leaves Westford, Train B, traveling 70 mph, leaves Eastford heading toward Westford. After how many hours the two trains meet?
Answers
Answer:
2.357 hours.
Step-by-step explanation:
Given:
(i) The distance between Westford and Eastford is 260 Miles.
(ii) Train A with a velocity of 70 Miles per Hour (mph) leaves Westford towards Eastford and travel for one hour.
(iii) After one hour Train B leaves Eastford towards Westford with a velocity 70 mph.
Now, after one hour Train A will travel 70 Miles to reach point P(say) and the distance between the Train A and Train B remains (260-70) = 190 Miles.
Since the velocity of the two trains is the same, so, they will travel an equal distance to meet each other.
So, Train A or Train B will travel (190/2) =95 Miles to meet with each other.
Hence, Train A or Train B travel 70 Miles in 1 hour.
⇒ Train A or Train B travel 95 miles in (95/70) =1.357 hours.
Therefore, after (1.357+1) = 2.357 hours Train A and Train B will meet each other.
(Answer)