train accelerated from 10km/hr to 40km/hr in 2 minutes. How much distance does it cover in this period? Assume that the tracks are straight?
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Answer:
The distance covered by the train is about 172 metres. For the conversion multiply by to the initial velocity. The train covers about 172 metres.
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please mark it and brainlieast
Explanation:
u = 10 km/h = 10 × 5/18 m/s = 25/9 m/s
v = 40 km/h = 40 × 5/18 m/s = 100/9 m/s
t = 2 min = 120 s
a = (v-u)/t = (100/9 – 25/9)/120 = 75/(9 × 120) = 5/72 m/s²
S = ut + ½ at²
S = 25/9 × 120 + ½ × 5/72 × 120²
S = 1000/3 + 500
S = 2500/3
S = 833.33 m
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