Train accelerated from 20 kilometre per hour to 80 km per hour in minutes how much distance does it cover in this period assume that the tracks are straight
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Answer:
1.32km
Explanation:
given,
v = 80 km/h
u= 20 km/h
t = 4 min = 0.066 hr
v = u+a t
a = v - u/ t
= (80 - 20 )/ 0.066
= 909.09 km/h2
v2-u2 = 2 a s
6400 - 4000 = 2 × 909.09× s
s = 1.32 km
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