Question

train accelerates from 36 km/h to 54 km/h in 10 sec.
(i) Acceleration
(ii) The distance travelled by car.​

Answer 1

Step-by-step explanation:

v2 = 54 kmph = 54×1000/60×60 = 15 m/s

v1 = 36 kmph = 36× 1000/60×60 = 10 m/s

t = 10s

i)acceleration = v2-v1/t

= 15-10/ 10 = 0.5 m/s²

ii) distance =( v2+v1/2) × t

= 10×(15+10)/2 = 5* 25=125 m