Question

train accelerates uniformly from 54 km/h to 90 km/h in 40 s. Find the distance

covered by the train​

Answer 1

u=54km/h=54*5/18=15m/s.; v=72km/h=72^ * 5/18=20m/s . t = 10s; a=v-u/t.; a = 20 - 15/10 . a = 5/10; a=1/5.; a = 0.2 m/s . s=ut+at2/2 . s = 150 + 20/2 . s = 150 + 10 . s = 160m .