Question

train covered a certain distance at a uniform speed if the train would have been 10 km/h faster if it would have taken 2 hour less than schedule time and if train were 10 km/h slower than it would take 8 hour more than schedule time find the distance covered by the train​

Answer 1

Answer

I had done one correction it is written in your question that train would take 8 hr more than scheduled time. But it will lead to negative time which is not possible.

So here I replaced it by 3hr.

To find,

• Distance covered by the train

Solution ,

Let the speed of the train be xkm/h and the time taken by train to travel the given distance be t hours and the distance to travel be dkm. We know that,

$\rm Speed = \frac { Distance } { Time }$

$\rm x = \frac { d } { t }$

d = xt -----------(1)

1st Case

⇛(x + 10)×(t − 2) = d

⇛ xt + 10t − 2x − 20 = d

⇛ d + 10t − 2x − 20 = d

⇛ −2x + 10t = 20 -----------(2)

2nd Case

⇛ (x − 10)×(t + 3) = d

⇛xt − 10t + 3x − 30 = d

⇛ d − 10t + 3x − 30 = d

⇛ 3x − 10t = 30 -----------(3)

Adding equations (2) and (3) we get

⇛ x = 50

Substitute the value of x in (2) we get

⇒ (−2)×(50) + 10t = 20

⇒ −100 + 10t = 20

⇒ 10t = 120

⇒t = 12 hr

Substitute the value of t and x in equation (1), we get,

Distance travelled = d = xt

⇒ d = 12×50 = 600Km

Hence, the distance covered by the train is 600km.

Answer 2

Answer:

600

Step-by-step explanation:

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