Question

train covered a certain distance at a uniform speed. If the train would

have been 6 km/h faster, it would have taken 4 hours less than the scheduled

time. And, if the train were slower by 6 km/h, it would have taken 6 hours

more than the scheduled time. Find the length of the journey.​

Answer 1

Answer:

Step-by-step explanation:

Let x km/hr be the speed of train .

Let y be the time taken by the train .

Distance =speed × time

Xy = Putting in 1 equation

So, (x+6) (y-4)=xy

xy-xy-4x+6y=24

-4x+6y=24 -- this is the 1 equation

Divided by (-2) 2x-3y= -12

there is second equation solve

So, (x-6) (y+6)=xy

xy+6x-6y-36=xy

xy-xy+6x-6y=36

6x-6y=16

Divided by 6 x-y=6--- this is the 2 equation

2x-3y=-2

(2)×2---2x-2y=12

-y=-24

y=24

Then, substitute method solve

y=24 in---1 equation

2x-72 =-12

2x=-12+72

2x=60

x=60/2

x=30

Then, we find the spped of he train = 30km

Time taken by he train =24km

Distance is coverd by train =xy

=30×24=720

2x-3y=-12

2 (30)-3 (24)=-12

60-72=-12

-12=-12

=1

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Answer 2

Answer:

please mark me as brainliest