Question

train covered a certain distance at a uniform speed. If the train had been 30km/h faster,

It would have taken 2 hour less than the scheduled time. If the train were slower by 15km/h,

It would have taken 2 hour more than the scheduled time. Find the length of the journey. ​

Answer 1

Answer:

360 km

Step-by-step explanation:

Let  

The actual speed of the train be x km/hr and  

The scheduled time be y hours.

Then,  

The distance of the journey = speed x time =xy

According to the question, we have

(x+30)(y−2)=xy

⇒xy=2x+30y−60=xy

⇒−2x+30y=60    … (i)

And,

(x=15)(y+2)=xy

⇒xy−15y+2x−30=xy

⇒2x−15y=30    … (ii)

Adding equations (i) and (ii), we have

15y=90

⇒y=  

15

90

​  

 

⇒y=6

On substituting the value of y in equation (i), we have

−2x+30(6)=60

⇒−2x+180=60

⇒−2x=60−180=−120

⇒x=  

−2

−120

​  

 

⇒x=60

Therefore, the distance of the journey =60×6=360 km