Train covered a certain distance at uniform speed. If the train had been 6 km/h faster, then have taken 8 hours less than the scheduled time. And, if the train were slower by 6 km/h, then the would have taken 12 hours more than the scheduled time . 140 % of the length of journey is
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Step-by-step explanation:
take square both sides
(ax+by)^2 = xy
ax^2+by^2+2axby = xy
now 2axby is constant so we can neglect it
hence prove
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