Question

train de running at a uniform speed to cover the distance between two cities, or the train had
been 30kmh faster. It would have taken 12 hours to complete the journey. If the train had been
8km/h slower, it would have taken 18 hours to complete the journey. Find
a. The speed of the train
b. The length of the journey​

Answer 1

Answer:

Step-by-step explanation:

Let the speed of train be v

Speed =Distance/time

Distance = speed ×time

Let the distance be x

A/Q

x = (V+30) ×12 ----------------- (i)

and x = (V-8)×18----------------------(ii)

From equation ( i ) and (ii) we have

(V+30)×12= (V-8)×18

12V+360=18V-144

360+144=18V-12V

504=6V

V=504/6

V=84

Therefore the speed of the train =84km/h

By putting V=84 in equation (i) we have

x=(84+30)×12

x=144×12

x=1368

Therefore the length of journey=1368km