train is travelling at a speed of 90 km per hour brakes are applied so as to produce a uniform acceleration of -3.5 metre per second square find how far the train will go before it is brought to rest
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Answer:
Answer. When brakes are applied, the uniform acceleration of the train is -0.6 m/s²
Explanation:
Answer:
Explanation:
We can use the equation of motion
v^2 = u^2 + 2as
Where v = final velocity
U = initial velocity
A = acceleration
S = distance travelled
As the train has to stop v = 0
U = 90km/h = 90*(5/18) = 25m/s
A = -0.5m/s^2
S = ?
Using the equation
0 = (25)^2 + 2(-0.5)(S)
0= 625 -1(S)
-625 = -S
Distance travelled before stopping = 625 metre
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