train is travelling at a speed of 90 km per hour brakes are applied so as to produce a uniform acceleration of -3.5 metre per second find how far the train will go before it is brought to rest
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Answer:v=u+at
0=90+(-3.5)t
T=90/3.5
T=25.7sec
S=ut+0.5at^2
S=90+0.5*-3.5*25*25
S=1093m
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