Physics, asked by harsh12gujjar, 7 months ago

train moves with a uniform velocity of 27 kmh−1 for 15 s. The distance covered by it is *

Answers

Answered by Anonymous
7

Answer:

112.5 metres

Explanation:

Given:

Uniform velocity with which the train moves = 27 km/h

27 km/h = 27 \times \frac{5}{18} = 7.5 m/s

Time = 15 seconds

To find:

Distance covered by the train with a uniform velocity of 27 km/h for 15 seconds

We know that :

Distance = Speed×Time

Substituting the above values, we get:

Distance = 7.5×15

Distance = 112.5 metres

1000 metres = 1 kilometre

Distance = 0.1125 kilometres

The train will move a distance of 0.1125 kilometres or 112.5 metres with a uniform velocity of 27 km/h for 15 seconds

Answered by Divadisha
4

Answer:

distance=112.5m

or d= 0.1125km

Explanation:

Given,

speed, s= 27km/h

              = (27*5/18) m/s

              = 15/2 m/s

time, t= 15s

we know that,

speed= distance/time

distance= speed * time

d=15/2*15

d=225/2 m

d=112.5m  

d=0.1125km

Hope it helps.....thank you            

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