train R takes 5 hours less than train S for covering a distance of 750 km .If the average speed of train R is 25km/h more than that of train S, find the average speed of both the train.
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r = the average speed of train R, r>0
s = the average speed of train S, s>0
the average speed of train R is 25 km/hr more than that of the train S
r = 25 + s
since avg.speed = distance/time => time = distance/avg.speed
train R takes 5 hours less than train S for covering a distance of 750 km
750/r = 750/s - 5
plug r = 25 + s into the last equation
750/(25 + s) = 750/s - 5
by solving we find and consider the positive roots
s = 50 km/hr
r = 25 + 50
r = 75 km/hr
the average speed of train R is 75 km/hr.
the average speed of train S is 50 km/hr.
s = the average speed of train S, s>0
the average speed of train R is 25 km/hr more than that of the train S
r = 25 + s
since avg.speed = distance/time => time = distance/avg.speed
train R takes 5 hours less than train S for covering a distance of 750 km
750/r = 750/s - 5
plug r = 25 + s into the last equation
750/(25 + s) = 750/s - 5
by solving we find and consider the positive roots
s = 50 km/hr
r = 25 + 50
r = 75 km/hr
the average speed of train R is 75 km/hr.
the average speed of train S is 50 km/hr.
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